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http://mathworld.wolfram.com/CompactSupport.html
Jan 02, 2020 · A function has compact support if it is zero outside of a compact set. Alternatively, one can say that a function has compact support if its support is a compact set. For example, the function f:x->x^2 in its entire domain (i.e., f:R->R^+) does not have compact support, while any bump function does have compact support.
https://www.encyclopediaofmath.org/index.php/Function_of_compact_support
The support of is the closure of the set of points for which is different from zero . Thus one can also say that a function of compact support in is a function defined on such that its support is a closed bounded set located at a distance from the boundary of by a number greater than , where is sufficiently small.
https://en.wikipedia.org/wiki/Compact_support
For example, if f : [0,1] → R is the Dirichlet function that is 0 on irrational numbers and 1 on rational numbers, and [0,1] is equipped with Lebesgue measure, then the support of f is the entire interval [0,1], but the essential support of f is empty, since f is equal almost everywhere to the zero function.
https://ocw.mit.edu/courses/mathematics/18-101-analysis-ii-fall-2005/lecture-notes/lecture14.pdf
3.9 Support and Compact Support Now for some terminology. Let U be an open set in Rn, and let f : U → R be a continuous function. Definition 3.26. The support of fis supp f= x∈ U: f(x) = 0}. (3.164) For example, supp f Q = Q. Definition 3.27. Let f : U → R be a continuous function. The function f is compactly supported if supp fis ...
https://math.stackexchange.com/questions/284045/example-of-a-function-with-compact-support
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https://en.wikipedia.org/wiki/Bump_function
Examples. The function : → given by = { (− −), ∈ (−,),is an example of a bump function in one dimension. It is clear from the construction that this function has compact support, since a function of the real line has compact support if and only if it has bounded and closed support.
https://math.stackexchange.com/questions/1283783/an-example-of-an-infinitely-differentiable-function-with-compact-support
Could anyone give me a function infinitely differentiable on the real line and having a compact support? And the function must be nonnegative and normalized, i.e. the integration of the function on the real line must be one. I tried to think of one myself, but it seems trickier than expected.
https://www.researchgate.net/publication/259260858_Continuous_functions_with_compact_support
We show, in particular, that for continuous frames, the pointfree rings of continuous functions with compact support are Noetherian if and only if the underlying set of the frame is finite; see ...
https://www.mathworks.com/help/stats/classreg.learning.regr.compactregressionsvm-class.html
Description. CompactRegressionSVM is a compact support vector machine (SVM) regression model. It consumes less memory than a full, trained support vector machine model (RegressionSVM model) because it does not store the data used to train the model.Because the compact model does not store the training data, you cannot use it to perform certain tasks, such as cross validation.
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