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https://answers.yahoo.com/question/index?qid=20140330124930AArGozm
Mar 29, 2014 · A steel cable is to support an elevator whose total (loaded) mass is not to exceed 2700kg . The tensile strength is of steel is5.0×10^8N/m2.? If the maximum acceleration of the elevator is 1.5m/s2 , calculate the minimum diameter of cable required.
https://www.chegg.com/homework-help/questions-and-answers/steel-cable-support-elevator-whose-total-loaded-mass-exceed-2600--maximum-acceleration-ele-q2340033
A steel cable is to support an elevator whose total (loaded) mass is not to exceed 2600 . If the maximum acceleration of the elevator is 1.1 , calculate the diameter of cable required. Assume a safety factor of 6.5. Use the tensile strength of steel = 5x10^8.
https://study.com/academy/answer/a-steel-cable-is-to-support-an-elevator-whose-total-loaded-mass-is-not-to-exceed-3100-kg-the-tensile-strength-of-steel-is-5-0-times-10-8-n-m-2-if-the-maximum-acceleration-of-the-elevator-is-1-3.html
Answer to: A steel cable is to support an elevator whose total (loaded) mass is not to exceed 3100 kg. The tensile strength of steel is 5.0 times...
https://www.chegg.com/homework-help/questions-and-answers/steel-cable-support-elevator-whose-total-loaded-mass-exceed-3500-kg-tensile-strength-steel-q20362389
A steel cable is to support an elevator whose total (loaded) mass is not to exceed 3500 kg. The tensile strength of steel is 5.0 times 10^8 N/m^2. If the maximum acceleration of the elevator is 1.4 m/s^2, calculate the minimum diameter of cable required.
https://www.coursehero.com/file/p2o34mj/48-Ill-A-steel-cable-is-to-support-an-elevator-whose-total-loaded-mass-is-not/
(Ill) A steel cable is to support an elevator whose total (loaded) mass is not to exceed 3100 kg. If the maximum acceleration of the elevator is 1.2 m/s2, calculate the diam- eter of cable required.
http://www.angelfire.com/nc3/pweb/lessons/fracture.htm
A steel cable is to support an elevator whose total loaded mass is not to exceed 3100 kg. If the maximum acceleration of the elevator is 1.2 m s -2 , calculate the diameter of the cable required with a safety factor of 7.0?
https://study.com/academy/answer/a-steel-cable-whose-cross-sectional-area-is-7-5-cm-2-is-used-to-support-an-elevator-cab-weighing-2-5-x-10-4-n-if-the-stress-in-the-cable-is-not-the-to-exceed-20-of-the-cable-elastic-limit-2-5-x-10-8.html
Answer to: A steel cable whose cross-sectional area is 7.5 cm^2 is used to support an elevator cab weighing 2.5 x 10^4 N. If the stress in the...
https://www.chegg.com/homework-help/questions-and-answers/steel-cable-used-support-elevator-cage-bottom-2-000-ft-deep-mineshaft-uniform-normal-strai-q4292180
A steel cable is used to support an elevator cage at the bottom of a 2,000 ft deep mineshaft. A uniform normal strain of 250 uin/in is produced in the cable by weight of the cage. At each point, the weight of the cable produces an additional normal strain that is porportional to the length of the cable below the point.
https://www.bekaert.com/en/products/construction/elevators/elevator-rope-wire
Bekaert has a full range of elevator rope wire of bright phosphated and redrawn galvanized wires. They are ideal for the creation of elevator ropes because of their high tensile strength and excellent ductility. On the rope level, these properties lead to optimal fatigue performance.
http://physicstasks.eu/1289/mine-shaft-elevator
A mine shaft elevator is hanging on a steel rope with a diameter of 2.5 cm. The total mass of the cabin and the transported people is 650 kg. Neglect the mass of the rope with respect to the mass of the cabin.
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